What is the derivative of 3^x+5 ?

The derivative of 3^x+5 is ln(3)*3^x

What is the first derivative of 3^x+5 ?

The first derivative of 3^x+5 is ln(3)*3^x

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\frac{d}{d x} (3^{x} + 5)

ln (3) \cdot 3^{x}

Solution steps

\frac{d}{d x} (3^{x} + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3^{x}) + \frac{d}{d x} (5)

\frac{d}{d x} (3^{x}) = 3^{x} ln (3)

\frac{d}{d x} (5) = 0

= 3^{x} ln (3) + 0

Simplify

= ln (3) \cdot 3^{x}

d er i v a t i v e \frac{x}{x ^{2} + 25}

\int \frac{- 2 ln ( x )}{x} d x

\int x^{2} 0. 4^{- x} d x

\int \frac{y ^{2}}{( 4 - y ^{2} ) ^{\frac{3}{2}}} d y

t an g e n t f (x) = - 18 x - \frac{17}{x}

What is the derivative of 3^x+5 ?
The derivative of 3^x+5 is ln(3)*3^x
What is the first derivative of 3^x+5 ?
The first derivative of 3^x+5 is ln(3)*3^x