derivative 3+vt-4.9t^2

Lösung

ableitung von

3 + v t - 4.9 t^{2}

t

Schritte zur Lösung

\frac{d}{d v} (3 + v t - 4.9 t^{2})

Behandle

t

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d v} (3) + \frac{d}{d v} (v t) - \frac{d}{d v} (4.9 t^{2})

\frac{d}{d v} (3) = 0

\frac{d}{d v} (v t) = t

\frac{d}{d v} (4.9 t^{2}) = 0

= 0 + t - 0

Vereinfache

= t

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