(dy)/(dt)=45t^8

解答

\frac{d y}{d t} = 45 t^{8}

y = 5 t^{9} + c_{1}

求解步骤

\frac{d y}{d t} = 45 t^{8}

替代

\frac{d y}{d t}

与

y^{'} (t)

y^{^{'}} (t) = 45 t^{8}

若

f^{^{'}} (x) = g (x)

则

f (x) = \int g (x) d x

y = \int 45 t^{8} d t

\int 45 t^{8} d t = 5 t^{9} + c_{1}

y = 5 t^{9} + c_{1}

\frac{d}{d x} (3 (ln (x) + 1))

y^{^{''}} + y^{^{'}} + \frac{1}{4} y = 0

f (x) = 3 x^{3} - 3 x

\int \frac{x ^{3} - 2 x ^{2} + 4 x}{x} d x

\frac{d y}{d x} = y^{2} - 9