y^{''}+25y=tsin(2t)

Lösung

y^{^{''}} + 25 y = t sin (2 t)

y = c_{1} cos (5 t) + c_{2} sin (5 t) + \frac{t sin ( 2 t )}{21} - \frac{4}{441} cos (2 t)

Schritte zur Lösung

y^{''} (t) + 25 y = t sin (2 t)

Solve linear ODE:

y = c_{1} cos (5 t) + c_{2} sin (5 t) + \frac{t sin ( 2 t )}{21} - \frac{4}{441} cos (2 t)

y = c_{1} cos (5 t) + c_{2} sin (5 t) + \frac{t sin ( 2 t )}{21} - \frac{4}{441} cos (2 t)

\frac{d}{d x} (0.5 e^{- 0.5 (x - 1)})

\frac{\partial}{\partial x} (\frac{1}{2 cos ^{2} ( x )})

\int 3 x^{2} + x d x

x \to 10 - lim (\frac{1}{( x - 10 ) ^{2}})

d er i v a t i v e f (x) = e^{θ} sin (6 θ)