derivative f(x)=e^θsin(6θ)

Lösung

ableitung von

f (x) = e^{θ} sin (6 θ)

\frac{d θ}{d x} = 0

Schritte zur Lösung

f (x) = e^{θ} sin (6 θ)

Behandle

θ

wie

θ (x)

Beide Seiten differenzieren:

0 = e^{θ} \frac{d θ}{d x} sin (6 θ) + cos (6 θ) \cdot 6 \frac{d θ}{d x} e^{θ}

Isoliere

\frac{d θ}{d x} : \frac{d θ}{d x} = 0

\frac{d θ}{d x} = 0

x \to 2 lim (3 x^{2} - x + 5)

\frac{\partial}{\partial x} (- 5 x^{2} - 5 y^{2} + x y)

y y^{^{'}} = 3 (\frac{y ^{2} - 2}{x ^{3}}) x^{2}

\frac{d}{d x} ((\frac{x + 9}{x - 9})^{5})

x \to - 6 - lim (\frac{x + 2}{x + 6})