(\partial)/(\partial y)(50y+3000-100x)

Lösung

\frac{\partial}{\partial y} (50 y + 3000 - 100 x)

50

Schritte zur Lösung

\frac{\partial}{\partial y} (50 y + 3000 - 100 x)

Behandle

x

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (50 y) + \frac{\partial}{\partial y} (3000) - \frac{\partial}{\partial y} (100 x)

\frac{\partial}{\partial y} (50 y) = 50

\frac{\partial}{\partial y} (3000) = 0

\frac{\partial}{\partial y} (100 x) = 0

= 50 + 0 - 0

Vereinfache

= 50

\frac{\partial}{\partial x} (\frac{59}{( 1 + x ^{2} + y ^{2} )})

s l o p e (1 - x - x^{2}) (x - 2), at x = 1

(1 + x^{2}) y^{^{'}} + 4 x y = x, y (0) = 1

\int \frac{2}{( 1 - 2 x ) ^{2}} d x

\int_{- 1}^{0} e^{- x} d x