(dN)/(dt)+N=Nte^{t+6}

Lösung

\frac{d N}{d t} + N = Nt e^{t + 6}

N = e^{e^{6 + t} t - e^{6 + t} - t + c_{1}}

Schritte zur Lösung

\frac{d N}{d t} + N = Nt e^{t + 6}

Solve separable ODE:

N = e^{e^{6 + t} t - e^{6 + t} - t + c_{1}}

N = e^{e^{6 + t} t - e^{6 + t} - t + c_{1}}

\frac{d}{d x} (\frac{x - 6}{x + 6})

\int \frac{x ^{3}}{a} - \frac{a}{x ^{2}} d x

a re a y = e^{x}, y = e^{2 x}, x = 0, x = ln (4)

\frac{\partial}{\partial y} (y^{x} - ln (x^{3} y + 6 x))

x \to - 4 + lim (\frac{- 6 x}{x + 4})