What is the integral of 3cos(θ) ?

The integral of 3cos(θ) is 3sin(θ)+C

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integral of 3cos(θ)

\int 3 cos (θ) d θ

3 sin (θ) + C

Solution steps

\int 3 cos (θ) d θ

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int cos (θ) d θ

Use the common integral:

\int cos (θ) d θ = sin (θ)

= 3 sin (θ)

Add a constant to the solution

= 3 sin (θ) + C

\frac{d}{d x} (- 3 x^{- 2})

\frac{\partial}{\partial x} (e^{x yz})

s l o p e - 3 x^{2} + 4 x + 4

x \to 1 - lim (\frac{x ^{2} + 1}{x - 1})

t an g e n t y = \frac{- 8 x}{x ^{2} + 1}, (0, 0)