What is the derivative of ln^2(3x) ?

The derivative of ln^2(3x) is (2ln(3x))/x

What is the first derivative of ln^2(3x) ?

The first derivative of ln^2(3x) is (2ln(3x))/x

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\frac{d}{d x} (ln^{2} (3 x))

\frac{2 ln ( 3 x )}{x}

Solution steps

\frac{d}{d x} (ln^{2} (3 x))

Apply the chain rule:

2 ln (3 x) \frac{d}{d x} (ln (3 x))

= 2 ln (3 x) \frac{d}{d x} (ln (3 x))

\frac{d}{d x} (ln (3 x)) = \frac{1}{x}

= 2 ln (3 x) \frac{1}{x}

Simplify

2 ln (3 x) \frac{1}{x} : \frac{2 ln ( 3 x )}{x}

= \frac{2 ln ( 3 x )}{x}

in v erse l a pl a ce F (s) = (\frac{2}{s} - \frac{1}{s ^{3}})^{2}

\int (1 + 2 x^{2}) e^{x^{2}} d x

x \to 3 lim (x 13 - x^{2})

\int_{1}^{2} x d x

in v erse l a pl a ce \frac{5 e ^{- 2 s}}{s ^{2} + 4}

What is the derivative of ln^2(3x) ?
The derivative of ln^2(3x) is (2ln(3x))/x
What is the first derivative of ln^2(3x) ?
The first derivative of ln^2(3x) is (2ln(3x))/x