What is the integral from 1 to 2 of sqrt(x) ?

The integral from 1 to 2 of sqrt(x) is (4sqrt(2)-2)/3

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integral from 1 to 2 of sqrt(x)

\int_{1}^{2} x d x

\frac{4 2 - 2}{3}

Decimal

1.21895 \dots

Solution steps

\int_{1}^{2} x d x

Apply the Power Rule

= [\frac{2}{3} x^{\frac{3}{2}}]_{1}^{2}

Compute the boundaries:

\frac{4 2}{3} - \frac{2}{3}

= \frac{4 2}{3} - \frac{2}{3}

Simplify

= \frac{4 2 - 2}{3}

in v erse l a pl a ce \frac{5 e ^{- 2 s}}{s ^{2} + 4}

\frac{\partial}{\partial y} (T x^{5} y^{4} z^{8})

a re a \frac{x ^{2}}{x ^{3} - 3 x}, \frac{1}{x ^{3} - 3 x}, 2, 11

\frac{d}{d x} (\frac{x e ^{x}}{sin ( x ) + 1})

d er i v a t i v e tan^{2} (3 x)

What is the integral from 1 to 2 of sqrt(x) ?
The integral from 1 to 2 of sqrt(x) is (4sqrt(2)-2)/3