y^'=y(xy^2+5)

Lösung

y^{^{'}} = y (x y^{2} + 5)

y = \frac{5 2 e ^{5 x}}{- 10 e ^{10 x} x + e ^{10 x} + c _{1}}, y = - \frac{5 2 e ^{5 x}}{- 10 e ^{10 x} x + e ^{10 x} + c _{1}}

Schritte zur Lösung

y^{'} (x) = y (x y^{2} + 5)

Solve Bernoulli ODE:

y = \frac{5 2 e ^{5 x}}{- 10 e ^{10 x} x + e ^{10 x} + c _{1}}, y = - \frac{5 2 e ^{5 x}}{- 10 e ^{10 x} x + e ^{10 x} + c _{1}}

y = \frac{5 2 e ^{5 x}}{- 10 e ^{10 x} x + e ^{10 x} + c _{1}}, y = - \frac{5 2 e ^{5 x}}{- 10 e ^{10 x} x + e ^{10 x} + c _{1}}

\int 3 (x) cos (\frac{x}{3}) d x

\frac{d}{d x} ((x - 1) \cdot x^{2} - 2 x + 2)

\int \frac{2}{x ^{3} + x ^{2}} d x

\frac{d}{d y} (y^{\frac{2}{3}})

d er i v a t i v e y = (t^{2} + 8)^{2} - 2 (t^{2} + 8)