limit as t approaches 0 of ((5e^t-5))/t

Lösung

t \to 0 lim (\frac{( 5 e ^{t} - 5 )}{t})

5

Schritte zur Lösung

t \to 0 lim (\frac{5 e ^{t} - 5}{t})

Wende das L'Hopital Theorem an

= t \to 0 lim (\frac{5 e ^{t}}{1})

Setze den Wert

t = 0

ein

= \frac{5 e ^{0}}{1}

Vereinfache

= 5

y^{^{''}} - 8 y^{^{'}} + 13 y = 0, y (0) = 0, y^{^{'}} (0) = 5

\int_{- \infty}^{0} x e^{9 x} d x

\frac{\partial}{\partial y} (y^{3} - y)

d er i v a t i v e f (x) = x^{2} - 8

in v erse l a pl a ce \frac{s + 1}{s ^{2} ( s + 2 ) ^{3}}