derivative of (sin(2x+1)/(cos(-1-2x)))

解答

\frac{d}{d x} (\frac{sin ( 2 x + 1 )}{cos ( - 1 - 2 x )})

sec^{2} (1 + 2 x) \cdot 2

求解步骤

\frac{d}{d x} (\frac{sin ( 2 x + 1 )}{cos ( - 1 - 2 x )})

化简

\frac{sin ( 2 x + 1 )}{cos ( - 1 - 2 x )} : tan (1 + 2 x)

= \frac{d}{d x} (tan (1 + 2 x))

使用连锁律:

sec^{2} (1 + 2 x) \frac{d}{d x} (1 + 2 x)

= sec^{2} (1 + 2 x) \frac{d}{d x} (1 + 2 x)

\frac{d}{d x} (1 + 2 x) = 2

= sec^{2} (1 + 2 x) \cdot 2

\frac{d ^{2}}{d x ^{2}} (cos (6 x))

x \to - 1 lim (x (0))

x \to 0 lim (3 f (x) (x^{2}))

\int cos (3 x) d x

x \to 0 + lim (x ln (2 x))