y^{'''}-6y^{''}+12y^'-8y=0

Lösung

y^{^{'''}} - 6 y^{^{''}} + 12 y^{^{'}} - 8 y = 0

y = c_{1} e^{2 t} + c_{2} t e^{2 t} + c_{3} t^{2} e^{2 t}

Schritte zur Lösung

y^{'''} (t) - 6 y^{''} (t) + 12 y^{'} (t) - 8 y = 0

Solve linear ODE:

y = c_{1} e^{2 t} + c_{2} t e^{2 t} + c_{3} t^{2} e^{2 t}

y = c_{1} e^{2 t} + c_{2} t e^{2 t} + c_{3} t^{2} e^{2 t}

(e^{x} cos (y) + 2 x) d x - (e^{x} sin (y)) d y = 0

x^{^{'}} = (x - 4)^{2}

d er i v a t i v e \frac{( e ^{2 p} + 1 )}{3 e ^{2 p}}

x \to 7 + lim (- 2 x^{2} + 2)

d er i v a t i v e sin (9 x) + sin^{2} (9 x)