(e^xcos(y)+2x)dx-(e^xsin(y))dy=0

解

(e^{x} cos (y) + 2 x) d x - (e^{x} sin (y)) d y = 0

y = arccos (\frac{c _{1} - x ^{2}}{e ^{x}}) + 2 πn, y = - arccos (\frac{c _{1} - x ^{2}}{e ^{x}}) + 2 πn

解答ステップ

(e^{x} cos (y) + 2 x) d x - (e^{x} sin (y)) d y = 0

完全 ODE を解く:

y = arccos (\frac{c _{1} - x ^{2}}{e ^{x}}) + 2 πn, y = - arccos (\frac{c _{1} - x ^{2}}{e ^{x}}) + 2 πn

y = arccos (\frac{c _{1} - x ^{2}}{e ^{x}}) + 2 πn, y = - arccos (\frac{c _{1} - x ^{2}}{e ^{x}}) + 2 πn