y^'=((t-y))/2

Lösung

y^{^{'}} = \frac{( t - y )}{2}

y = t - 2 + \frac{c _{1}}{e ^{\frac{t}{2}}}

Schritte zur Lösung

y^{'} (t) = \frac{( t - y )}{2}

Solve linear ODE:

y = t - 2 + \frac{c _{1}}{e ^{\frac{t}{2}}}

y = t - 2 + \frac{c _{1}}{e ^{\frac{t}{2}}}

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