What is area y=sqrt(x),y=x-2,[0,4] ?

The answer to area y=sqrt(x),y=x-2,[0,4] is 16/3

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area y=sqrt(x),y=x-2,[0,4]

area

y = x, y = x - 2, [0, 4]

\frac{16}{3}

Decimal

5.33333 \dots

Solution steps

Apply the area formula:

\int_{0}^{4} x - (x - 2) d x

Solve

\int_{0}^{4} x - (x - 2) d x : \frac{16}{3}

The area is:

= \frac{16}{3}

\frac{\partial}{\partial x} (2 x^{2} + 4 y^{2} - 3 z^{2} - 11)

\int (cos (t)) d t

\int \frac{x ^{4} + 12 x ^{2} + 1}{x ^{5} + 20 x ^{3} + 5 x} d x

d er i v a t i v e - 9 cos (3 x)

\int \frac{( x - 1 ) ^{2}}{2} d x

What is area y=sqrt(x),y=x-2,[0,4] ?
The answer to area y=sqrt(x),y=x-2,[0,4] is 16/3