(dy)/(dx)=x^2y^2+x^2+y^2+1

Lösung

\frac{d y}{d x} = x^{2} y^{2} + x^{2} + y^{2} + 1

y = tan (\frac{x ^{3}}{3} + x + c_{1})

Schritte zur Lösung

\frac{d y}{d x} = x^{2} y^{2} + x^{2} + y^{2} + 1

Solve separable ODE:

y = tan (\frac{x ^{3}}{3} + x + c_{1})

y = tan (\frac{x ^{3}}{3} + x + c_{1})

\int_{0}^{1} (e^{\frac{2 x}{3}} + 1) d x

y^{^{''}} + (2 \cdot 0.1096) y^{^{'}} + (4.51 5^{2}) y = 0

(t^{2} + 9) y^{^{'}} + 2 t y = t^{2} (t^{2} + 9)

\int + \frac{x}{x ^{2} + 9} d x

\frac{\partial}{\partial x} (\frac{x + 4}{y + 3})