What is inverse oflaplace 1/(0.1s+1) ?

The answer to inverse oflaplace 1/(0.1s+1) is 10e^{-10t}

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inverse oflaplace 1/(0.1s+1)

inverse laplace

\frac{1}{0.1 s + 1}

10 e^{- 10 t}

Solution steps

L^{- 1} {\frac{1}{0.1 s + 1}}

= L^{- 1} {10 \cdot \frac{1}{s + 10}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 10 L^{- 1} {\frac{1}{s + 10}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s + 10}} = e^{- 10 t}

= 10 e^{- 10 t}

\int (3 e^{x} + 5) d x

\frac{d}{d x} (\frac{8 x ^{6} - 125 b ^{9}}{2 x ^{2} - 5 b ^{3}})

(2 x + 1)^{5} (x^{3} - x + 1)^{4}

\frac{d}{d x} (e^{x} (x - 5) + 5)

x \frac{d y}{d x} - y = 6 x^{2}

What is inverse oflaplace 1/(0.1s+1) ?
The answer to inverse oflaplace 1/(0.1s+1) is 10e^{-10t}