What is the integral of (3e^x+sqrt(5)) ?

The integral of (3e^x+sqrt(5)) is 3e^x+sqrt(5)x+C

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integral of (3e^x+sqrt(5))

\int (3 e^{x} + 5) d x

3 e^{x} + 5 x + C

Solution steps

\int 3 e^{x} + 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 e^{x} d x + \int 5 d x

\int 3 e^{x} d x = 3 e^{x}

\int 5 d x = 5 x

= 3 e^{x} + 5 x

Add a constant to the solution

= 3 e^{x} + 5 x + C

\frac{d}{d x} (\frac{8 x ^{6} - 125 b ^{9}}{2 x ^{2} - 5 b ^{3}})

(2 x + 1)^{5} (x^{3} - x + 1)^{4}

\frac{d}{d x} (e^{x} (x - 5) + 5)

x \frac{d y}{d x} - y = 6 x^{2}

y^{^{''}} + 2 y^{^{'}} - 3 y = e^{t} + e^{- t}

What is the integral of (3e^x+sqrt(5)) ?
The integral of (3e^x+sqrt(5)) is 3e^x+sqrt(5)x+C