What is the derivative of 2x^{-1} ?

The derivative of 2x^{-1} is -2/(x^2)

What is the first derivative of 2x^{-1} ?

The first derivative of 2x^{-1} is -2/(x^2)

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\frac{d}{d x} (2 x^{- 1})

- \frac{2}{x ^{2}}

Solution steps

\frac{d}{d x} (2 x^{- 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 (- 1 \cdot x^{- 1 - 1})

Simplify

2 (- 1 \cdot x^{- 1 - 1}) : - \frac{2}{x ^{2}}

= - \frac{2}{x ^{2}}

\int_{4}^{6} \frac{y}{y ^{2} - 3} d y

\frac{d}{d x} (\frac{x ^{3}}{48} + \frac{4}{x})

\int \frac{1}{sin ( x ) tan ( x )} d x

\int \frac{17}{x} d x

\frac{1}{a s + 1}

What is the derivative of 2x^{-1} ?
The derivative of 2x^{-1} is -2/(x^2)
What is the first derivative of 2x^{-1} ?
The first derivative of 2x^{-1} is -2/(x^2)