integral of 6x+3x^2+12x^3+C

Lösung

\int 6 x + 3 x^{2} + 12 x^{3} + C d x

3 x^{2} + x^{3} + 3 x^{4} + C x + C

Schritte zur Lösung

\int 6 x + 3 x^{2} + 12 x^{3} + C d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 6 x d x + \int 3 x^{2} d x + \int 12 x^{3} d x + \int C d x

\int 6 x d x = 3 x^{2}

\int 3 x^{2} d x = x^{3}

\int 12 x^{3} d x = 3 x^{4}

\int C d x = C x

= 3 x^{2} + x^{3} + 3 x^{4} + C x

Füge eine Konstante zur Lösung hinzu

= 3 x^{2} + x^{3} + 3 x^{4} + C x + C

d er i v a t i v e \frac{( 3 t ^{2} + 4 )}{4 t + 4}

\int \frac{csc ( θ ) cot ( θ )}{9} d θ

\frac{d}{d x} (x^{2} 4 x - 9)

\int - cos (u) + \frac{1}{3} cos^{3} (u) d u

d er i v a t i v e (3 x^{2} - 10)^{- 13}