y^{''}+25y=25sec^2(5x)

Lösung

y^{^{''}} + 25 y = 25 sec^{2} (5 x)

y = c_{1} cos (5 x) + c_{2} sin (5 x) - 1 + ln (sec (5 x) + tan (5 x)) sin (5 x)

Schritte zur Lösung

y^{''} (x) + 25 y = 25 sec^{2} (5 x)

Solve linear ODE:

y = c_{1} cos (5 x) + c_{2} sin (5 x) - 1 + ln (sec (5 x) + tan (5 x)) sin (5 x)

y = c_{1} cos (5 x) + c_{2} sin (5 x) - 1 + ln (sec (5 x) + tan (5 x)) sin (5 x)

\frac{\partial}{\partial x} (x^{\frac{1}{2}} + y^{\frac{1}{3}})

\int_{81}^{v} \frac{1}{v} d v

\int (25 - x^{2}) d x

d er i v a t i v e x^{2} sin^{7} (x) + x cos^{- 3} (x)

\int 0.2 x + 8 d x