y^'=(xy^3)/(sqrt(1+x^2))

Lösung

y^{^{'}} = \frac{x y ^{3}}{1 + x ^{2}}

y = - \frac{x ^{2} + 1 - c _{1}}{2 x ^{2} + 2 - 2 c _{1}^{2}}, y = - - \frac{x ^{2} + 1 - c _{1}}{2 x ^{2} + 2 - 2 c _{1}^{2}}

Schritte zur Lösung

y^{'} (x) = \frac{x y ^{3}}{1 + x ^{2}}

Solve separable ODE:

y = - \frac{x ^{2} + 1 - c _{1}}{2 x ^{2} + 2 - 2 c _{1}^{2}}, y = - - \frac{x ^{2} + 1 - c _{1}}{2 x ^{2} + 2 - 2 c _{1}^{2}}

y = - \frac{x ^{2} + 1 - c _{1}}{2 x ^{2} + 2 - 2 c _{1}^{2}}, y = - - \frac{x ^{2} + 1 - c _{1}}{2 x ^{2} + 2 - 2 c _{1}^{2}}

\int \frac{e ^{4 x}}{e ^{4 x} + 6} d x

n = 1 \sum \infty \frac{5}{2 ^{n}}

t an g e n t y = \frac{2 x}{x + 1}, at x = 1

2 \frac{d y}{d x} + 4 y = 1

t a y l or f (x) = cos (x^{4})