zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的微积分 >

tangent f(x)= 1/(x+9),\at x=-7

解答

切线

f (x) = \frac{1}{x + 9}, at x = - 7

解答

y = - \frac{1}{4} x - \frac{5}{4}

求解步骤

找到切点:

(- 7, \frac{1}{2})

计算

f (x) = \frac{1}{x + 9}

的斜率:

\frac{df ( x )}{d x} = - \frac{1}{( x + 9 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{4}

找到斜率 m=

- \frac{1}{4}

且穿过

(- 7, \frac{1}{2})

的直线:

y = - \frac{1}{4} x - \frac{5}{4}

y = - \frac{1}{4} x - \frac{5}{4}

作图

流行的例子

(\partial)/(\partial x)(3ye^{4xy}+8x)

\frac{\partial}{\partial x} (3 y e^{4 x y} + 8 x)

integral of 3/(12x-1)

\int \frac{3}{12 x - 1} d x

f (x) = \frac{x}{e ^{x}}

(\partial)/(\partial x)(x^2-xy+8y^2)

\frac{\partial}{\partial x} (x^{2} - x y + 8 y^{2})

integral from 0 to 1 of 5e^{-2sqrt(x)}

\int_{0}^{1} 5 e^{- 2 x} d x