(\partial)/(\partial z)(x^2+3yz+4xy)

Lösung

\frac{\partial}{\partial z} (x^{2} + 3 yz + 4 x y)

3 y

Schritte zur Lösung

\frac{\partial}{\partial z} (x^{2} + 3 yz + 4 x y)

Behandle

x, y

als Konstanten

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial z} (x^{2}) + \frac{\partial}{\partial z} (3 yz) + \frac{\partial}{\partial z} (4 x y)

\frac{\partial}{\partial z} (x^{2}) = 0

\frac{\partial}{\partial z} (3 yz) = 3 y

\frac{\partial}{\partial z} (4 x y) = 0

= 0 + 3 y + 0

Vereinfache

= 3 y

n = 0 \sum \infty 6 (0.4)^{n}

\frac{d}{d x} (k y (x)^{2})

y^{^{''}} - y = 3 e^{x}

\frac{d}{d x} ((\frac{1}{x ^{2}} + 3) (x^{2} - \frac{1}{x ^{2}} + 3))

n \to \infty lim (\frac{( - 1 ) ^{n + 1}}{2 n - 1})