What is the solution for (dy)/(dt)= 1/(2y+1) ?

The solution for (dy)/(dt)= 1/(2y+1) is y=(-1+sqrt(1-4(-c_{1)-t)})/2 ,y=(-1-sqrt(1-4(-c_{1)-t)})/2

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(dy)/(dt)= 1/(2y+1)

\frac{d y}{d t} = \frac{1}{2 y + 1}

y = \frac{- 1 + 1 - 4 ( - c _{1} - t )}{2}, y = \frac{- 1 - 1 - 4 ( - c _{1} - t )}{2}

Solution steps

\frac{d y}{d t} = \frac{1}{2 y + 1}

Solve separable ODE:

y = \frac{- 1 + 1 - 4 ( - c _{1} - t )}{2}, y = \frac{- 1 - 1 - 4 ( - c _{1} - t )}{2}

y = \frac{- 1 + 1 - 4 ( - c _{1} - t )}{2}, y = \frac{- 1 - 1 - 4 ( - c _{1} - t )}{2}

t an g e n t f (x) = \frac{x}{x + 1}, at x = 1

d er i v a t i v e (x^{2} - x) \cdot e^{- x}

\int \frac{2 x + 4}{x ^{3} - 2 x ^{2}} d x

\int π cos (n x) d x

\int_{0}^{1} 6 e^{- 6 x} d x

What is the solution for (dy)/(dt)= 1/(2y+1) ?
The solution for (dy)/(dt)= 1/(2y+1) is y=(-1+sqrt(1-4(-c_{1)-t)})/2 ,y=(-1-sqrt(1-4(-c_{1)-t)})/2