What is the limit as x approaches 1-of 2^{1/(x-1)} ?

The limit as x approaches 1-of 2^{1/(x-1)} is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 1-of 2^{1/(x-1)}

x \to 1 - lim (2^{\frac{1}{x - 1}})

0

Solution steps

x \to 1 - lim (2^{\frac{1}{x - 1}})

Apply exponent rules

= x \to 1 - lim (e^{\frac{1}{x - 1} l n (2)})

Apply the Limit Chain Rule:

0

= 0

\frac{d}{d x} (ln^{6} (x))

θ sin (θ)

\frac{d y}{d x} + 7 y - 2 e^{- x} = 0

\frac{d}{d x} (5 arcsin (x^{3}))

x y^{^{'}} - 2 y = 2 x^{2} ln (x)

What is the limit as x approaches 1-of 2^{1/(x-1)} ?
The limit as x approaches 1-of 2^{1/(x-1)} is 0