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Popular Calculus >

xy^'-2y=2x^2ln(x)

Solution

x y^{^{'}} - 2 y = 2 x^{2} ln (x)

Solution

y = ln^{2} (x) x^{2} + c_{1} x^{2}

Solution steps

x y^{'} (x) - 2 y = 2 x^{2} ln (x)

Solve linear ODE:

y = ln^{2} (x) x^{2} + c_{1} x^{2}

y = ln^{2} (x) x^{2} + c_{1} x^{2}

Graph

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y^3dx+3xy^2dy=0

y^{3} d x + 3 x y^{2} d y = 0

integral of ((2x^2+5))/(x^2+1)

\int \frac{( 2 x ^{2} + 5 )}{x ^{2} + 1} d x

limit as x approaches infinity of x+6

x \to \infty lim (x + 6)

Frequently Asked Questions (FAQ)

What is the solution for xy^'-2y=2x^2ln(x) ?
The solution for xy^'-2y=2x^2ln(x) is y=ln^2(x)x^2+c_{1}x^2