What is the derivative of (x^2+4^5) ?

The derivative of (x^2+4^5) is 10x(x^2+4)^4

What is the first derivative of (x^2+4^5) ?

The first derivative of (x^2+4^5) is 10x(x^2+4)^4

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\frac{d}{d x} ((x^{2} + 4)^{5})

10 x (x^{2} + 4)^{4}

Solution steps

\frac{d}{d x} ((x^{2} + 4)^{5})

Apply the chain rule:

5 (x^{2} + 4)^{4} \frac{d}{d x} (x^{2} + 4)

= 5 (x^{2} + 4)^{4} \frac{d}{d x} (x^{2} + 4)

\frac{d}{d x} (x^{2} + 4) = 2 x

= 5 (x^{2} + 4)^{4} \cdot 2 x

Simplify

= 10 x (x^{2} + 4)^{4}

\int_{0}^{\frac{π}{4}} sin^{2} (2 x) d x

d er i v a t i v e f (x) = ln (sin (x))

d er i v a t i v e 15 x \cdot ln (20 x)

x \to 1 lim ((x^{2} - 9)^{\frac{1}{3}})

\frac{d}{d x} (x e^{x^{5}})

What is the derivative of (x^2+4^5) ?
The derivative of (x^2+4^5) is 10x(x^2+4)^4
What is the first derivative of (x^2+4^5) ?
The first derivative of (x^2+4^5) is 10x(x^2+4)^4