x(dy)/(dx)+1=x+y

Lösung

x \frac{d y}{d x} + 1 = x + y

y = x ln (x) + 1 + c_{1} x

Schritte zur Lösung

x \frac{d y}{d x} + 1 = x + y

Solve linear ODE:

y = x ln (x) + 1 + c_{1} x

y = x ln (x) + 1 + c_{1} x

\frac{\partial}{\partial y} (6 - 3 x - 2 y)

\int_{- \infty}^{- 1} e^{- 34 t} d t

n = 1 \sum \infty \frac{2 n}{1 + n ^{4}}

x^{3} y^{^{'}} + 2 x^{2} y = 2 cos (3 x) y^{- \frac{1}{2}}

x \to \infty lim (\frac{2 x ^{2} - 9 x - 2}{- 5 x ^{2} - 10 x + 3})