integral of ((4x+3)(2x^2+3x)^3)

解答

\int ((4 x + 3) (2 x^{2} + 3 x)^{3}) d x

4 x^{8} + 24 x^{7} + 54 x^{6} + 54 x^{5} + \frac{81 x ^{4}}{4} + C

求解步骤

\int (4 x + 3) (2 x^{2} + 3 x)^{3} d x

乘开

(4 x + 3) (2 x^{2} + 3 x)^{3} : 32 x^{7} + 168 x^{6} + 324 x^{5} + 270 x^{4} + 81 x^{3}

= \int 32 x^{7} + 168 x^{6} + 324 x^{5} + 270 x^{4} + 81 x^{3} d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 32 x^{7} d x + \int 168 x^{6} d x + \int 324 x^{5} d x + \int 270 x^{4} d x + \int 81 x^{3} d x

\int 32 x^{7} d x = 4 x^{8}

\int 168 x^{6} d x = 24 x^{7}

\int 324 x^{5} d x = 54 x^{6}

\int 270 x^{4} d x = 54 x^{5}

\int 81 x^{3} d x = \frac{81 x ^{4}}{4}

= 4 x^{8} + 24 x^{7} + 54 x^{6} + 54 x^{5} + \frac{81 x ^{4}}{4}

解答补常数

= 4 x^{8} + 24 x^{7} + 54 x^{6} + 54 x^{5} + \frac{81 x ^{4}}{4} + C

\frac{d ^{2}}{d x ^{2}} ((9 x^{2} + 6)^{7})

s l o p e (- 2.5) (- 4.1)

\frac{d}{d x} (400 x)

\int csc^{2} (x) 3 + cot (x) d x

(e^{- 2 x})^{^{'}}