What is the solution for (dy)/(dx)y=(4x)/(sqrt(3x-2x^2)) ?

The solution for (dy)/(dx)y=(4x)/(sqrt(3x-2x^2)) is

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(dy)/(dx)y=(4x)/(sqrt(3x-2x^2))

\frac{d y}{d x} y = \frac{4 x}{3 x - 2 x ^{2}}

y = 32 arcsin (\frac{4}{3} x - 1) - 2 - 16 x^{2} + 24 x + c_{1}, y = - 32 arcsin (\frac{4}{3} x - 1) - 2 - 16 x^{2} + 24 x + c_{1}

Solution steps

\frac{d y}{d x} y = \frac{4 x}{3 x - 2 x ^{2}}

Solve separable ODE:

y = 32 arcsin (\frac{4}{3} x - 1) - 2 - 16 x^{2} + 24 x + c_{1}, y = - 32 arcsin (\frac{4}{3} x - 1) - 2 - 16 x^{2} + 24 x + c_{1}

y = 32 arcsin (\frac{4}{3} x - 1) - 2 - 16 x^{2} + 24 x + c_{1}, y = - 32 arcsin (\frac{4}{3} x - 1) - 2 - 16 x^{2} + 24 x + c_{1}

What is the solution for (dy)/(dx)y=(4x)/(sqrt(3x-2x^2)) ?
The solution for (dy)/(dx)y=(4x)/(sqrt(3x-2x^2)) is