What is the derivative of 1.4x^5-2.5x^2+6.7 ?

The derivative of 1.4x^5-2.5x^2+6.7 is 7x^4-5x

What is the first derivative of 1.4x^5-2.5x^2+6.7 ?

The first derivative of 1.4x^5-2.5x^2+6.7 is 7x^4-5x

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\frac{d}{d x} (1.4 x^{5} - 2.5 x^{2} + 6.7)

7 x^{4} - 5 x

Solution steps

\frac{d}{d x} (1.4 x^{5} - 2.5 x^{2} + 6.7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1.4 x^{5}) - \frac{d}{d x} (2.5 x^{2}) + \frac{d}{d x} (6.7)

\frac{d}{d x} (1.4 x^{5}) = 7 x^{4}

\frac{d}{d x} (2.5 x^{2}) = 5 x

\frac{d}{d x} (6.7) = 0

= 7 x^{4} - 5 x + 0

Simplify

= 7 x^{4} - 5 x

What is the derivative of 1.4x^5-2.5x^2+6.7 ?
The derivative of 1.4x^5-2.5x^2+6.7 is 7x^4-5x
What is the first derivative of 1.4x^5-2.5x^2+6.7 ?
The first derivative of 1.4x^5-2.5x^2+6.7 is 7x^4-5x