What is the derivative of ln(x-x) ?

The derivative of ln(x-x) is 1/x-1

What is the first derivative of ln(x-x) ?

The first derivative of ln(x-x) is 1/x-1

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\frac{d}{d x} (ln (x) - x)

\frac{1}{x} - 1

Solution steps

\frac{d}{d x} (ln (x) - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (ln (x)) - \frac{d x}{d x}

\frac{d}{d x} (ln (x)) = \frac{1}{x}

\frac{d x}{d x} = 1

= \frac{1}{x} - 1

\int e^{6 x - 3} d x

t an g e n t f (x) = x (36 + x^{2})^{- \frac{1}{2}}, at x = 0

d er i v a t i v e 113 t - 0.5 t^{4} + 900

\frac{d}{d x} (\frac{1}{x e ^{x}})

\frac{\partial}{\partial s} (3 s + t)

What is the derivative of ln(x-x) ?
The derivative of ln(x-x) is 1/x-1
What is the first derivative of ln(x-x) ?
The first derivative of ln(x-x) is 1/x-1