What is the (3sqrt(x-1)+4sqrt(5-x))^' ?

The (3sqrt(x-1)+4sqrt(5-x))^' is 3/(2sqrt(x-1))-2/(sqrt(5-x))

What is the first (3sqrt(x-1)+4sqrt(5-x))^' ?

The first (3sqrt(x-1)+4sqrt(5-x))^' is 3/(2sqrt(x-1))-2/(sqrt(5-x))

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(3 x - 1 + 4 5 - x)^{^{'}}

\frac{3}{2 x - 1} - \frac{2}{5 - x}

Solution steps

(3 x - 1 + 4 5 - x)^{'}

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= (3 x - 1)^{^{'}} + (4 5 - x)^{^{'}}

(3 x - 1)^{'} = \frac{3}{2 x - 1}

(4 5 - x)^{'} = - \frac{2}{5 - x}

= \frac{3}{2 x - 1} - \frac{2}{5 - x}

\int \frac{1}{5 x} d x

\frac{d}{d x} (ln (x - x^{2} - 1))

\int 16 - x^{2} x d x

\int_{0}^{3} (3 - x)^{2} d x

y^{^{''}} + 5 y^{^{'}} + 4 y = 8 t e^{2 t}

What is the (3sqrt(x-1)+4sqrt(5-x))^' ?
The (3sqrt(x-1)+4sqrt(5-x))^' is 3/(2sqrt(x-1))-2/(sqrt(5-x))
What is the first (3sqrt(x-1)+4sqrt(5-x))^' ?
The first (3sqrt(x-1)+4sqrt(5-x))^' is 3/(2sqrt(x-1))-2/(sqrt(5-x))