What is the derivative of ln(8x^2) ?

The derivative of ln(8x^2) is 2/x

What is the first derivative of ln(8x^2) ?

The first derivative of ln(8x^2) is 2/x

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\frac{d}{d x} (ln (8 x^{2}))

\frac{2}{x}

Solution steps

\frac{d}{d x} (ln (8 x^{2}))

Apply the chain rule:

\frac{1}{8 x ^{2}} \frac{d}{d x} (8 x^{2})

= \frac{1}{8 x ^{2}} \frac{d}{d x} (8 x^{2})

\frac{d}{d x} (8 x^{2}) = 16 x

= \frac{1}{8 x ^{2}} \cdot 16 x

Simplify

\frac{1}{8 x ^{2}} \cdot 16 x : \frac{2}{x}

= \frac{2}{x}

d er i v a t i v e x^{2} + 4 x - 2

n = 1 \sum \infty 2^{- n} + 3^{- n}

t an g e n t - 9 x^{\frac{1}{3}} + 5, at x = 4

\frac{\partial}{\partial z} (ln (x + z) - yz)

y^{^{''}} + 4 y = x

What is the derivative of ln(8x^2) ?
The derivative of ln(8x^2) is 2/x
What is the first derivative of ln(8x^2) ?
The first derivative of ln(8x^2) is 2/x