derivative of arccot(2x)

解答

\frac{d}{d x} (arccot (2 x))

- \frac{2}{4 x ^{2} + 1}

求解步骤

\frac{d}{d x} (arccot (2 x))

使用连锁律:

- \frac{1}{( 2 x ) ^{2} + 1} \frac{d}{d x} (2 x)

= - \frac{1}{( 2 x ) ^{2} + 1} \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - \frac{1}{( 2 x ) ^{2} + 1} \cdot 2

化简

- \frac{1}{( 2 x ) ^{2} + 1} \cdot 2 : - \frac{2}{4 x ^{2} + 1}

= - \frac{2}{4 x ^{2} + 1}

\int \frac{7 ( x ^{2} + 5 )}{x ( x ^{2} + 7 )} d x

a re a 3 x^{3} - x^{2} - 10 x, - x^{2} + 2 x, [- 2, 2]

\int_{- 2}^{0} 2 x^{2} + 5 x + 6 d x

d er i v a t i v e f (x) = - \frac{3}{2} x^{3} + \frac{2}{5} x^{2} - 4

d er i v a t i v e g (t) = \frac{7}{8 t ^{5}}