derivative of 15ln(x+4cos(x)+o)

Lösung

\frac{d}{d x} (15 ln (x) + 4 cos (x) + o)

\frac{15}{x} - 4 sin (x)

Schritte zur Lösung

\frac{d}{d x} (15 ln (x) + 4 cos (x) + o)

Behandle

o

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (15 ln (x)) + \frac{d}{d x} (4 cos (x)) + \frac{d o}{d x}

\frac{d}{d x} (15 ln (x)) = \frac{15}{x}

\frac{d}{d x} (4 cos (x)) = - 4 sin (x)

\frac{d o}{d x} = 0

= \frac{15}{x} - 4 sin (x) + 0

Vereinfache

= \frac{15}{x} - 4 sin (x)

\frac{d}{d x} ((4 x^{2} - 3 x) (2 x + 1))

f (x) = 2 x^{2} cos (4 x)

n = 1 \sum \infty \frac{n}{2 n - 1}

d er i v a t i v e 1 - lo g_{e} (x)

\frac{\partial}{\partial z} (\frac{2 x - 2 z}{3 y + 2 z})