derivative of (4x^2-3x(2x+1))

Lösung

\frac{d}{d x} ((4 x^{2} - 3 x) (2 x + 1))

24 x^{2} - 4 x - 3

Schritte zur Lösung

\frac{d}{d x} ((4 x^{2} - 3 x) (2 x + 1))

Wende die Produktregel an:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 4 x^{2} - 3 x, g = 2 x + 1

= \frac{d}{d x} (4 x^{2} - 3 x) (2 x + 1) + \frac{d}{d x} (2 x + 1) (4 x^{2} - 3 x)

\frac{d}{d x} (4 x^{2} - 3 x) = 8 x - 3

\frac{d}{d x} (2 x + 1) = 2

= (8 x - 3) (2 x + 1) + 2 (4 x^{2} - 3 x)

Vereinfache

(8 x - 3) (2 x + 1) + 2 (4 x^{2} - 3 x) : 24 x^{2} - 4 x - 3

= 24 x^{2} - 4 x - 3

f (x) = 2 x^{2} cos (4 x)

n = 1 \sum \infty \frac{n}{2 n - 1}

d er i v a t i v e 1 - lo g_{e} (x)

\frac{\partial}{\partial z} (\frac{2 x - 2 z}{3 y + 2 z})

\int \frac{4 x}{x ^{2} + 4 x + 4} d x