(\partial)/(\partial y)(6+xln(xy-5))

Lösung

\frac{\partial}{\partial y} (6 + x ln (x y - 5))

\frac{x ^{2}}{x y - 5}

Schritte zur Lösung

\frac{\partial}{\partial y} (6 + x ln (x y - 5))

Behandle

x

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (6) + \frac{\partial}{\partial y} (x ln (x y - 5))

\frac{\partial}{\partial y} (6) = 0

\frac{\partial}{\partial y} (x ln (x y - 5)) = \frac{x ^{2}}{x y - 5}

= 0 + \frac{x ^{2}}{x y - 5}

Vereinfache

= \frac{x ^{2}}{x y - 5}

\int 3 sin^{3} (x) cos^{7} (x) d x

a re a x = 16 - y^{2}, x = y^{2} - 16

n = 6 \sum \infty \frac{3 n}{12 n}

y^{^{'''}} + y^{^{'}} = 2 x^{2}

d er i v a t i v e f (x) = e^{t a n (x)}