What is the integral of (-2)/(5x^2) ?

The integral of (-2)/(5x^2) is 2/(5x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (-2)/(5x^2)

\int \frac{- 2}{5 x ^{2}} d x

\frac{2}{5 x} + C

Solution steps

\int \frac{- 2}{5 x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{- 2}{5} \cdot \int \frac{1}{x ^{2}} d x

Simplify

= (- \frac{2}{5}) \cdot \int \frac{1}{x ^{2}} d x

Apply the Power Rule

= (- \frac{2}{5}) (- \frac{1}{x})

Simplify

(- \frac{2}{5}) (- \frac{1}{x}) : \frac{2}{5 x}

= \frac{2}{5 x}

Add a constant to the solution

= \frac{2}{5 x} + C

\frac{d y}{d x} - x y^{2} = 2 y x

\frac{d}{d x} (ln (\frac{3 - x}{3 + x}))

\int_{- 1}^{5} x - 3 x^{2} d x

\int \frac{lo g _{2} ( u )}{u} d x

\frac{d}{d x} (\frac{x}{1 - sin ( x )})