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Popular Calculus >

integral from-1 to 2 of (1-x)

Solution

\int_{- 1}^{2} (1 - x) d x

Solution

\frac{3}{2}

+1

Decimal

1.5

Solution steps

\int_{- 1}^{2} 1 - x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} 1 d x - \int_{- 1}^{2} x d x

\int_{- 1}^{2} 1 d x = 3

\int_{- 1}^{2} x d x = \frac{3}{2}

= 3 - \frac{3}{2}

Simplify

3 - \frac{3}{2} : \frac{3}{2}

= \frac{3}{2}

Graph

Popular Examples

sum from n=1 to infinity of 1/(3^n)

n = 1 \sum \infty \frac{1}{3 ^{n}}

integral of (3/2)^x

\int (\frac{3}{2})^{x} d x

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\int 9 sec^{4} (x) d x

derivative of 5x^4-3x^2+1/(sqrt(x)-7)

\frac{d}{d x} (5 x^{4} - 3 x^{2} + \frac{1}{x} - 7)

integral of 1/(3+3cos(x))

\int \frac{1}{3 + 3 cos ( x )} d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 2 of (1-x) ?
The integral from-1 to 2 of (1-x) is 3/2