implicit (dy)/(dx),8x+3y=7

Lösung

implizite ableitung

\frac{d y}{d x}, 8 x + 3 y = 7

\frac{d y}{d x} = - \frac{8}{3}

Schritte zur Lösung

8 x + 3 y = 7

Behandle

y

wie

y (x)

Beide Seiten differenzieren:

8 + 3 \frac{d y}{d x} = 0

Isoliere

\frac{d y}{d x} : \frac{d y}{d x} = - \frac{8}{3}

\frac{d y}{d x} = - \frac{8}{3}

\int tan^{\frac{1}{2}} (x) sec^{4} (x) d x

\frac{d}{d x} (\frac{1}{3} x^{3} + x^{2})

in v erse l a pl a ce \frac{( s + 1 )}{s ^{2} + s + \frac{1}{2}}

\int \frac{6}{( x - 2 ) ( x + 4 )} d x

\frac{\partial}{\partial x} ((3 x + 4 y)^{5})