integral of 2x^2-1

Lösung

\int 2 x^{2} - 1 d x

\frac{2 x ^{3}}{3} - x + C

Schritte zur Lösung

\int 2 x^{2} - 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x^{2} d x - \int 1 d x

\int 2 x^{2} d x = \frac{2 x ^{3}}{3}

\int 1 d x = x

= \frac{2 x ^{3}}{3} - x

Füge eine Konstante zur Lösung hinzu

= \frac{2 x ^{3}}{3} - x + C

d er i v a t i v e f (x) = a x^{3} + b x^{2} + c x + d

\int (9 x + cos (x)) d x

x \to - 4 lim (x - 4)

\frac{d}{d x} (I n (x + x^{2} + 1))

d er i v a t i v e 3 x^{2} - 7 x^{3} + x^{4} - 5 - 3 x