integral of (9x+cos(x))

Lösung

\int (9 x + cos (x)) d x

\frac{9 x ^{2}}{2} + sin (x) + C

Schritte zur Lösung

\int 9 x + cos (x) d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 9 x d x + \int cos (x) d x

\int 9 x d x = \frac{9 x ^{2}}{2}

\int cos (x) d x = sin (x)

= \frac{9 x ^{2}}{2} + sin (x)

Füge eine Konstante zur Lösung hinzu

= \frac{9 x ^{2}}{2} + sin (x) + C

x \to - 4 lim (x - 4)

\frac{d}{d x} (I n (x + x^{2} + 1))

d er i v a t i v e 3 x^{2} - 7 x^{3} + x^{4} - 5 - 3 x

y^{^{'}} = \frac{( t ^{2} + 3 y ^{2} )}{2 t y}

n = 0 \sum \infty (- \frac{7}{10})^{n}