What is the limit as x approaches infinity of 9.35e^{(-0.4x)}+5.52 ?

The limit as x approaches infinity of 9.35e^{(-0.4x)}+5.52 is 5.52

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

limit as x approaches infinity of 9.35e^{(-0.4x)}+5.52

x \to \infty lim (9.35 e^{(- 0.4 x)} + 5.52)

5.52

Solution steps

x \to \infty lim (9.35 e^{- 0.4 x} + 5.52)

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to \infty lim (9.35 e^{- 0.4 x}) + x \to \infty lim (5.52)

x \to \infty lim (9.35 e^{- 0.4 x}) = 0

x \to \infty lim (5.52) = 5.52

= 0 + 5.52

Simplify

= 5.52

x \to - 2 lim (\frac{x ^{2} + 2}{x + 2})

t a y l or \frac{1}{x} lo g_{10} (1 + x)

\frac{\partial}{\partial y} (9 - x^{2} - y^{2})

\frac{d}{d x} (x^{9} + 9^{x})

\int x (ln (x^{2})) d x

What is the limit as x approaches infinity of 9.35e^{(-0.4x)}+5.52 ?
The limit as x approaches infinity of 9.35e^{(-0.4x)}+5.52 is 5.52