What is the derivative of x^9+9^x ?

The derivative of x^9+9^x is 9x^8+2ln(3)*9^x

What is the first derivative of x^9+9^x ?

The first derivative of x^9+9^x is 9x^8+2ln(3)*9^x

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\frac{d}{d x} (x^{9} + 9^{x})

9 x^{8} + 2 ln (3) \cdot 9^{x}

Solution steps

\frac{d}{d x} (x^{9} + 9^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{9}) + \frac{d}{d x} (9^{x})

\frac{d}{d x} (x^{9}) = 9 x^{8}

\frac{d}{d x} (9^{x}) = 2 ln (3) \cdot 9^{x}

= 9 x^{8} + 2 ln (3) \cdot 9^{x}

\int x (ln (x^{2})) d x

ma c l a u r in e^{s i n (x)}

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What is the derivative of x^9+9^x ?
The derivative of x^9+9^x is 9x^8+2ln(3)*9^x
What is the first derivative of x^9+9^x ?
The first derivative of x^9+9^x is 9x^8+2ln(3)*9^x