derivative of arctan(x+1+2x-y)

Lösung

\frac{d}{d x} (arctan (x + 1) + 2 x - y)

\frac{1}{x ^{2} + 2 x + 2} + 2 - \frac{d y}{d x}

Schritte zur Lösung

\frac{d}{d x} (arctan (x + 1) + 2 x - y)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (arctan (x + 1)) + \frac{d}{d x} (2 x) - \frac{d y}{d x}

\frac{d}{d x} (arctan (x + 1)) = \frac{1}{x ^{2} + 2 x + 2}

\frac{d}{d x} (2 x) = 2

= \frac{1}{x ^{2} + 2 x + 2} + 2 - \frac{d y}{d x}

y^{^{''}} + 25 y = cos (2 x)

\int \frac{( x + 7 ) ^{5}}{x} d x

\frac{d y}{d x} = \frac{- y ^{2}}{1 + y ^{2}} \cdot e^{- x}

\frac{\partial}{\partial z} ((x + z) e^{x - y})

\int \frac{1}{9 e ^{- 2 x} + e ^{2 x}} d x