y^{''}+4y=sec^2(2x)

Lösung

y^{^{''}} + 4 y = sec^{2} (2 x)

y = c_{1} cos (2 x) + c_{2} sin (2 x) + \frac{- cos ( 2 x ) ( cos ( 2 x ) + sin ( 2 x ) tan ( 2 x ) ) + ln ( tan ( 2 x ) + sec ( 2 x ) ) sin ( 2 x )}{4}

Schritte zur Lösung

y^{''} (x) + 4 y = sec^{2} (2 x)

Solve linear ODE:

y = c_{1} cos (2 x) + c_{2} sin (2 x) + \frac{- cos ( 2 x ) ( cos ( 2 x ) + sin ( 2 x ) tan ( 2 x ) ) + ln ( tan ( 2 x ) + sec ( 2 x ) ) sin ( 2 x )}{4}

y = c_{1} cos (2 x) + c_{2} sin (2 x) + \frac{- cos ( 2 x ) ( cos ( 2 x ) + sin ( 2 x ) tan ( 2 x ) ) + ln ( tan ( 2 x ) + sec ( 2 x ) ) sin ( 2 x )}{4}

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